[ \det(A)=2\beginvmatrix4&5\1&0\endvmatrix -(-1)\beginvmatrix0&5\-2&0\endvmatrix +3\beginvmatrix0&4\-2&1\endvmatrix =2(4\cdot0-5\cdot1)+1(0\cdot0-5\cdot(-2))+3(0\cdot1-4\cdot(-2)) ]
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Área: (A(x)=x(24-x)=24x-x^2).
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De la segunda ecuación: (x = y+1). Sustituimos en la primera: